SSC Chemistry Assignment 2022 has been published. We Prepared all week (14th,13th,12th, 11th, 10th, 9th, 8th, 7th, 6th, 5th, 4th, 3rd, and 1st week) assignment Answer has been published for SSC Chemistry Assignment. Two assignments have been selected from the second chapter. The title of the second chapter is Cells and Tissues. So the solution or answer of 2 assignments from living cells and tissues has to be given. We will provide you with instructions on how to do all week SSC Chemistry assignments. We will also create an assignment and provide a sample for students who do not understand how to do the SSC assignment. You can download all week assignments of SSC Chemistry from our website.
SSC Chemistry 7th Week Assignment 2022
SSC 2022 Chemistry Assignment is scheduled for Science Group students. Students have to prepare SSC Chemistry Assignment Answer 2022 for a total of 14th weeks. The 1st-week assignment has already been published. Chemistry subject has been assigned for the 1st week. It has also been selected for the 3rd, 4th, 6th, 7th, 9th, 10th, and 14th weeks. The 2022 SSC examinee will have to prepare a total of 8 assignment solutions for Chemistry subjects and submit it to the school.
SSC Chemistry Assignment Answer 2022
SSC Chemistry Assignment 2022 Answer, If required, they can be taken help from their teachers, the internet, and others resources. Here you will find the SSC 2022 Chemistry Assignment Answer for all weeks. We will publish Chemistry Answer randomly for all weeks. You will also find next week's assignment solution here. You can create your Chemistry assignment with ideas from our solution.
āĻāϤ্āϤāϰ āϏāĻŽূāĻš
āϤাāϰিāĻ: ā§Ļā§Š āĻŽাāϰ্āĻ, ⧍ā§Ļ⧍⧍
āĻŦāϰাāĻŦāϰ,
āĻĒ্āϰāϧাāύ āĻļিāĻ্āώāĻ,
XYZ।
āύāĻŦাāĻŦāĻāĻ্āĻ, āĻĻিāύাāĻāĻĒুāϰ।
āĻŦিāώāϝ়: “āĻĒāϰ্āϝাāϝ় āϏাāϰāĻŖিāϰ āĻŽৌāϞেāϰ āĻĒāϰ্āϝাāϝ়āĻŦৃāϤ্āϤিāĻ āϧāϰ্āĻŽ” āϏāĻŽ্āĻĒāϰ্āĻিāϤ| āĻĒ্āϰāϤিāĻŦেāĻĻāύ।
āĻāύাāĻŦ, āĻŦিāύীāϤ āύিāĻŦেāĻĻāύ āĻāĻ āϝে, āĻāĻĒāύাā§ą āĻāĻĻেāĻļ āύং āϏ.āĻ.āĻ.āĻŦি ā§Šā§§ā§¯/ā§Ŧ āϤাāϰিāĻ: ā§Ļā§Š āĻŽাāϰ্āĻ, ⧍ā§Ļ⧍⧍ āĻ
āύুāϏাāϰে “āĻĒāϰ্āϝাāϝ় āϏাāϰāĻŖিāϰ āĻŽৌāϞেāϰ āĻĒāϰ্āϝাāϝ়āĻŦৃāϤ্āϤিāĻ āϧāϰ্āĻŽ ” āϏāĻŽ্āĻĒāϰ্āĻিāϤ āĻĒ্āϰāϤিāĻŦেāĻĻāύāĻি āύিāϝ়ে āĻĒেāĻļ āĻāϰāĻি।
āĻĒāϰ্āϝাāϝ āĻ āĻ্āϰুāĻĒেāϰ āϧাāϤāĻŦ āϧāϰ্āĻŽ āύিāϰ্āĻŖāϝ়ঃ
āĻāĻ্āϤ āĻāύ্āĻĄিāϤ āϏাāϰāĻŖিāϰ āĻ্āϰুāĻĒ-ā§§ āĻ ā§Š āύāĻŽ্āĻŦāϰ āĻĒāϰ্āϝাāϝ়েāϰ। āĻŽৌāϞāĻুāϞােāϰ āϧাāϤāĻŦ āϧāϰ্āĻŽ āύিāϰ্āĻŖāϝ় āĻāϰা āĻšāϞােঃ
āĻ্āϰুāĻĒ-ā§§ āĻāϰ āĻŽৌāϞ āĻুāϞাে āĻšāϞােঃ Li, Na, K, Rb, Cs āĻāϰ āϧাāϤāĻŦ āϧāϰ্āĻŽ āĻĒāϰ্āϝাāϝ়āĻ্āϰāĻŽে āĻāĻŦāϰ্āϤিāϤ āĻšāϝ়। āĻāĻŽāϰা āĻাāύি, āĻ্āϰুāĻĒ āĻ
āύুāϝাāϝ়ী āύিāĻেāϰ āĻĻিāĻে āĻেāϞে āĻŽৌāϞ āĻুāϞােāϰ āĻĒাāϰāĻŽাāĻŖāĻŦিāĻ āϏংāĻ্āϝা āĻŦৃāĻĻ্āϧিāϰ āϏাāĻĨে āϏাāĻĨে āύāϤুāύ āĻļāĻ্āϤিāϏ্āϤāϰ āϝুāĻ্āϤ āĻšāϝ় āĻāĻŦং āĻĒাāϰāĻŽাāĻŖāĻŦিāĻ āĻāĻাāϰ āĻŦৃāĻĻ্āϧি āĻĒাāϝ়। āĻĢāϞে āĻেāύ্āĻĻ্āϰ āĻĨেāĻে āϏāϰ্āĻŦāĻŦāĻšিঃāϏ্āĻĨ āϏ্āϤāϰেāϰ āĻāϞেāĻāĻ্āϰāύেāϰ āĻĻূāϰāϤ্āĻŦ āĻŦৃāĻĻ্āϧি āĻĒাāϝ়। āϝাāϰ āĻাāϰāĻŖে āĻŽৌāϞ āĻুāϞাে āϤাāĻĻেāϰ āĻāϞেāĻāĻ্āϰāύ āĻুāĻŦ āϏāĻšāĻেāĻ āϤ্āϝাāĻ āĻāϰāϤে āĻĒাāϰে। āϤাāĻ āĻ্āϰুāĻĒ āĻ
āύুāϝাāϝ়ী
āϝāϤ āύিāĻে āύাāĻŽা āϝাāϝ় āϤāϤāĻ āĻŽৌāϞāĻুāϞােāϰ āϧাāϤāĻŦ āϧāϰ্āĻŽ āĻŦাāĻĄ়āϤে āĻĨাāĻে।
āϧাāϤāĻŦ āϧāϰ্āĻŽেāϰ āĻ্āϰāĻŽ āĻšāϞােঃ Li<Na<K<Rb<Csā§Šāϝ় āĻĒāϰ্āϝাāϝেāϰ āĻŽৌāϞ āĻšāϞােঃ Na, Mg, P, cl āĻāϰা āĻāĻāĻ āĻĒāϰ্āϝাāϝ়েāϰ āĻŽৌāϞ। āĻāĻĻেāϰ āĻāϞেāĻāĻ্āϰāύ āĻŦৃāĻĻ্āϧিāϰ āϏাāĻĨে āϏাāĻĨে āύāϤুāύ āĻোāύ āĻļāĻ্āϤিāϏ্āϤāϰ āϝুāĻ্āϤ āĻšāϝ়āύা। āϤাāĻ āĻেāύ্āĻĻ্āϰেāϰ āĻāĻāϰ্āώāĻŖ āϧীāϰে āϧীāϰে āĻŦৃāĻĻ্āϧি āĻĒাāϝ় āĻāĻŦং āĻĒাāϰāĻŽাāĻŖāĻŦিāĻ āĻāĻাāϰ āĻš্āϰাāϏ āĻĒাāϝ়। āϤাāĻ āϤাāĻĻেāϰ āĻāϞেāĻāĻ্āϰāύ āϤ্āϝাāĻ āĻāϰাāϰ āĻ্āώāĻŽāϤা āĻš্āϰাāϏ āĻĒাāϝ়। āĻŽৌāϞāĻুāϞােāϰ āϧাāϤāĻŦ āϧāϰ্āĻŽেāϰ āĻ্āϰāĻŽ āĻšāϞােঃ Na>Mg>P>CI
āĻĒāϰ্āϝাāϝ় āĻ āĻ্āϰুāĻĒেāϰ āĻāϝুāύিāĻāϰāĻŖ āĻļāĻ্āϤি āύিāϰ্āĻŖāϝ়ঃ
āĻ্āϝাāϏীāϝ় āĻ
āĻŦāϏ্āĻĨাāϝ় āĻāĻ āĻŽােāϞ āϝাāϝ় āĻĒāϰāĻŽাāĻŖু āĻĨেāĻে āĻāĻ āĻŽােāϞ āĻāϞেāĻāĻ্āϰāύ āĻ
āĻĒāϏাāϰāĻŖ āĻāϰে āĻāĻ āĻŽােāϞ āϧāύাāϤ্āĻŽāĻ āĻāύে āĻĒāϰিāĻŖāϤ āĻāϰāϤে āϝে āĻĒāϰিāĻŽাāĻŖ āĻļāĻ্āϤিāϰ āĻĒ্āϰāϝােāĻāύ āĻšāϝ়, āϤাāĻে āĻ āĻŽৌāϞেāϰ āĻāϝ়āύিāĻāϰāĻŖ āĻļāĻ্āϤি āĻŦāϞে। |
āĻāĻ্āϤ āĻāύ্āĻĄিāϤ āϏাāϰāĻŖিāϰ āĻ্āϰুāĻĒ-⧍ āĻ ā§Ēāϰ্āĻĨ āύāĻŽ্āĻŦāϰ āĻĒāϰ্āϝাāϝ়েāϰ āĻŽৌāϞāĻুāϞােāϰ āĻāϝ়āύিāĻāϰāĻŖ āĻļāĻ্āϤি āύিāϰ্āĻŖāϝ় āĻāϰা āĻšāϞােঃ
āĻ্āϰুāĻĒ-⧍ āĻāϰ āĻŽৌāϞ āĻুāϞাে āĻšāϞাে: Be, Mg, ca, Sr, Ba āĻāϰ āĻāϝ়āύিāĻāϰāĻŖ āĻļāĻ্āϤি āĻĒāϰ্āϝাāϝ়āĻ্āϰāĻŽে āĻāĻŦāϰ্āϤিāϤ āĻšāϝ়। āĻāĻŽāϰা āĻাāύি, āĻ্āϰুāĻĒ āĻ
āύু্āϝাāϝ়ী āύিāĻেāϰ āĻĻিāĻে āĻেāϞে āĻŽৌāϞ āĻুāϞােāϰ āĻĒাāϰāĻŽাāĻŖāĻŦিāĻ āϏংāĻ্āϝা āĻŦৃāĻĻ্āϧিāϰ āϏাāĻĨে āϏাāĻĨে āĻĒাāϰāĻŽাāĻŖāĻŦিāĻ āĻāĻাāϰ āĻŦৃāĻĻ্āϧি āĻĒাāϝ়। āϝাāϰ āĻাāϰāĻŖে āĻŽৌāϞ āĻুāϞাে āϤাāĻĻেāϰ āĻāϞেāĻāĻ্āϰāύ āĻুāĻŦ āϏāĻšāĻেāĻ āϤ্āϝাāĻ āĻāϰāϤে āĻĒাāϰে। āĻāĻŦাāϰ āĻŽৌāϞেāϰ āĻāĻাāϰ āĻŦৃāĻĻ্āϧি āĻĒেāϞে āĻŽৌāϞেāϰ āĻāϝ়āύিāĻāϰāĻŖ āĻļāĻ্āϤি āĻāĻŽে। āĻাāĻ āĻ্āϰুāĻĒ āĻ
āύু্āϝাāϝ়ী āϝāϤ āύিāĻে āύাāĻŽা āϝাāϝ় āϤāϤāĻ āĻŽৌāϞāĻুāϞােāϰ āĻāϝ়āύিāĻāϰāĻŖ āĻļāĻ্āϤি āĻāĻŽāϤে āĻĨাāĻে।
ā§Ēāϰ্āĻĨ āĻĒāϰ্āϝাāϝেāϰ āĻŽৌāϞ āĻšāϞােঃ K, Ca, As, Br āĻāϰা āĻāĻāĻ āĻĒāϰ্āϝাāϝেāϰ āĻŽৌāϞ। āĻāĻĻেāϰ āĻāϞেāĻāĻ্āϰāύ āĻŦৃāĻĻ্āϧিāϰ āϏাāĻĨে āϏাāĻĨে āύāϤুāύ āĻোāύ āĻļāĻ্āϤিāϏ্āϤāϰ āϝুāĻ্āϤ āĻšāϝ়āύা। āϤাāĻ āĻেāύ্āĻĻ্āϰেāϰ āĻāĻāϰ্āώāĻŖ āϧীāϰে āϧীāϰে āĻŦৃāĻĻ্āϧি āĻĒাāϝ় āĻāĻŦং āĻĒাāϰāĻŽাāĻŖāĻŦিāĻ āĻāĻাāϰ āĻš্āϰাāϏ āĻĒাāϝ়। āϤাāĻ āϤাāĻĻেāϰ āϤāĻĄ়িā§ āĻāĻŖাāϤ্āĻŽāĻāϤা āĻŦৃāĻĻ্āϧি āĻĒাāϝ়। āϤāĻĄ়িā§ āĻāĻŖাāϤ্āĻŽāĻāϤাāϰ āĻ্āϰāĻŽ āĻšāϞােঃ K<Ca<As<Br
āĻ্āώাāϰāϧাāϤুāϏāĻŽূāĻšেāϰ āϝৌāĻেāϰ āĻāĻāĻ āϰāĻāĻŽ āĻŦিāĻ্āϰিāϝ়া āĻĒ্āϰāĻĻāϰ্āĻļāύঃ
āĻ্āϰুāĻĒ-ā§§ āĻāϰ āĻŽৌāϞ āĻুāϞােāĻে āĻ্āώাāϰ āϧাāϤু āĻŦāϞা āĻš্āϝ। āĻাāϰāĻŖ | āĻāϰা āĻĒাāύিāϰ āϏাāĻĨে āĻŦিāĻ্āϰিāϝ়া āĻāϰে āĻ্āώাāϰ āĻ H, āĻ্āϝাāϏ āϤৈāϰি āĻāϰে। āĻ্āϰুāĻĒ-ā§§ āĻāϰ āĻ্āώাāϰ āϧাāϤুāĻুāϞাে āĻšāϞােঃ Na, K, Rb, cs, Fr. | āĻāĻĻেāϰ āϏāϰ্āĻŦāĻļেāώ āĻāĻ্āώāĻĒāĻĨে 1āĻি āĻāϰে āĻāϞেāĻāĻ্āϰāύ āĻĨাāĻে। āϤাāĻ āϤাāϰা āϏāĻšāĻে 1āĻি āĻāϞেāĻāĻ্āϰāύ āϤ্āϝাāĻ āĻāϰে āĻāϝ়āύিāĻ āϝৌāĻ āϤৈāϰি āĻāϰāϤে āĻĒাāϰে। āĻāϰা āĻĒাāύিāϰ āϏাāĻĨে āĻŦিāĻ্āϰি āĻāϰে āĻ্āώাāϰ āĻ āĻšাāĻāĻĄ্āϰোāĻেāύ āĻ্āϝাāϏ āĻā§āĻĒāύ্āύ āĻāϰে। 2Li + 2Hā§Ļ = 2LiOH + H, | 2Na + 2HO = 2NaOH + H2 2K + 2Hā§Ļ = 2KOH + H, 2Rb + 2HO = 2RbOH + H,
āĻāĻŦাāϰ āĻāĻĻেāϰ āĻ্āώাāϰ āĻāϏিāĻĄেāϰ āϏাāĻĨে āĻŦিāĻ্āϰি āĻāϰে āϞāĻŦāĻŖ āĻ āĻĒাāύি āĻā§āĻĒāύ্āύ āĻāϰে।
LiOH + HCl = LiCl + HO NaOH + HCI = NaCl + H2O KOH + HCl = KCI + HO bOH + HCl = RbCl + Hā§Ļ āĻāĻĻেāϰ āϧāϰ্āĻŽ āĻāĻāĻ āĻšāĻāϝ়াāϝ় āĻāϰা āϏāϰ্āĻŦāĻĻা āĻāĻāĻ āĻŦিāĻ্āϰিāϝ়া āĻĒ্āϰāĻĻāϰ্āĻļāύ āĻāϰে। āĻ্āώাāϰ āϧাāϤুāϏāĻŽূāĻš āĻāĻāĻ āĻŦিāĻ্āϰিāϝ়া āĻĒ্āϰāĻĻāϰ্āĻļāύ āĻāϰে।
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